this post was submitted on 05 Dec 2024
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Advent Of Code

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An unofficial home for the advent of code community on programming.dev!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

AoC 2024

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Day 5: Print Queue

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  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
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FAQ

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[–] [email protected] 1 points 3 weeks ago* (last edited 3 weeks ago)

python

solution

import re
import aoc

def setup():
    lines = aoc.get_lines(5)
    return ([list(map(int, re.findall(r'\d+', x)))
             for x in lines if re.search(r'\|', x)],
            [list(map(int, re.findall(r'\d+', x)))
             for x in lines if re.search(r',', x)], 0)

def one():
    rules, updates, acc = setup()
    for update in updates:
        v = 1
        for i, u in enumerate(update):
            r = [x[0] for x in rules if x[1] == u and x[0] in update]
            if not all(n in update[:i] for n in r):
                v = 0
                break
        if v:
            acc += update[len(update) // 2]
    print(acc)

def fix(update, rules):
    c = 1
    while c:
        c = 0
        for i, u in enumerate(update):
            r = [x[0] for x in rules if x[1] == u and x[0] in update]
            for p in r:
                pi = update.index(p)
                if pi > i:
                    update[i], update[pi] = update[pi], update[i]
                    c = 1
    return update[len(update) // 2]

def two():
    rules, updates, acc = setup()
    for update in updates:
        v = 1
        for i, u in enumerate(update):
            r = [x[0] for x in rules if x[1] == u and x[0] in update]
            if not all(n in update[:i] for n in r):
                v = 0
                break
        if not v:
            acc += fix(update, rules)
    print(acc)

one()
two()