this post was submitted on 14 Dec 2024
15 points (100.0% liked)
Advent Of Code
985 readers
28 users here now
An unofficial home for the advent of code community on programming.dev!
Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.
AoC 2024
Solution Threads
M | T | W | T | F | S | S |
---|---|---|---|---|---|---|
1 | ||||||
2 | 3 | 4 | 5 | 6 | 7 | 8 |
9 | 10 | 11 | 12 | 13 | 14 | 15 |
16 | 17 | 18 | 19 | 20 | 21 | 22 |
23 | 24 | 25 |
Rules/Guidelines
- Follow the programming.dev instance rules
- Keep all content related to advent of code in some way
- If what youre posting relates to a day, put in brackets the year and then day number in front of the post title (e.g. [2024 Day 10])
- When an event is running, keep solutions in the solution megathread to avoid the community getting spammed with posts
Relevant Communities
Relevant Links
Credits
Icon base by Lorc under CC BY 3.0 with modifications to add a gradient
console.log('Hello World')
founded 1 year ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
Haskell, alternative approach
The x and y coordinates of robots are independent. 101 and 103 are prime. So, the pattern of x coordinates will repeat every 101 ticks, and the pattern of y coordinates every 103 ticks.
For the first 101 ticks, take the histogram of x-coordinates and test it to see if it's roughly randomly scattered by performing a chi-squared test using a uniform distrobution as the basis. [That code's not given below, but it's a trivial transliteration of the formula on wikipedia, for instance.] In my case I found a massive peak at t=99.
Same for the first 103 ticks and y coordinates. Mine showed up at t=58.
You're then just looking for solutions of t = 101m + 99, t = 103n + 58 [in this case]. I've a library function, maybeCombineDiophantine, which computes the intersection of these things if any exist; again, this is basic wikipedia stuff.
Very nice!
Very cool, taking a statistical approach to discern random noise from picture.
Thanks. It was the third thing I tried - began by looking for mostly-symmetrical, then asked myself "what does a christmas tree look like?" and wiring together some rudimentary heuristics. When those both failed (and I'd stopped for a coffee) the alternative struck me. It seems like a new avenue into the same diophantine fonisher that's pretty popular in these puzzles - quite an interesting one.
This day's puzzle is clearly begging for some inventive viaualisations.
I should add - it's perfectly possible to draw pictures which won't be spotted by this test, but in this case as it happens the distributions are exceedingly nonuniform at the critical point.