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So to be honest, 90% of the time the base of the logarithm doesn't really matter as long as we are consistent. The main property we use logarithms for is that log_b(xy) = log_b(x) + log_b(y), and this holds for any base b. In fact, the change-of-base formula tells us that we can get from one base to another just by multiplying by a constant (log_a(x) = log_b(x) * 1/log_b(a)), and so there is a strong desire to pick one canonical "logarithm" function, and just take care of any base silliness by multiplying your final result by a scaling factor if needed.
Given that, the natural logarithm is quite "natural" because it is the inverse of the exponential function, exp(x) = e^x. The exponential function itself is quite natural as it is the unique function f such that f(0) = 1 and f'(x) = f(x). Really, I would argue that the function exp(x) is the fundamentally important mathematical object -- the natural logarithm is important because it is that function's inverse, and the number e just happens to be the value of exp(1).
Your explanation makes a lot of sense to me! I didn't know that
exp'(x) = exp(x), but can see how this could be an interesting property and in turn makeslninteresting.You saying, that it often doesn't matter which logarithm is used, made me check and realize that
log_a(x)/log_a(y)is the same aslog_b(x)/log_b(y). Thus I understand that it really doesn't make a difference which logarithm is used when "comparing the magnitude" (not sure if this is the right term) of numbers.I feel like I have a much better understanding of
lnnow. I'll assume that the base of an algorithm is often basically a random choice and baseeis often used because of its "interesting trivia".Thanks a lot!