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Finding an instance that blocks least and is least blocked (lemmy.one)

submitted 1 year ago by [email protected] to c/[email protected]

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Is there a way to shop around for a Lemmy instance based on how many instances are blocking it and how many instances it's blocking? For example, I noticed that the lemmygrad.ml instance is relatively popular, but it seems like a lot of other instances block it. It also blocks a bunch of other instances. So, if there are any communities on there that might be relevant to me then I would be missing out. I guess I could just create an account on a walled instance, but I would prefer not to keep creating accounts. I'd like to just find one instance that maximizes my access. Is the answer to just run my own instance?

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[–] [email protected] 1 points 1 year ago (1 children)

if a liberal/anarchist/not-ML instance popped up and started behaving like Lemmygrad does, they'd get mass-defederated too. like i said, it's not their views they got defederated for, it's their behavior

[–] [email protected] -1 points 1 year ago (1 children)

Behaviour like what though? Disagreeing? I don't even know what 'sealioning' means, it basically seems like just saying 'this person has different fundamental assumptions to me therefore they're acting in bad faith'.

[–] [email protected] 1 points 1 year ago* (last edited 1 year ago) (1 children)

Lemmygrad has a history of brigading communities, targeted harassment towards admins and prolific political posters, and as i mentioned before, sealioning (defined by Wikipedia as "a type of trolling or harassment that consists of pursuing people with relentless requests for evidence, often tangential or previously addressed, while maintaining a pretense of civility and sincerity ('I'm just trying to have a debate'), and feigning ignorance of the subject matter")

[–] [email protected] -1 points 1 year ago

But how do you differentiate 'brigading' from just being outside the ideological orthodox of a given community? Shouldn't bad actors just be banned personally?