this post was submitted on 24 Mar 2024
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Hey guys i cant find any usefull guide on how USB c charging works in depth. In particular i have bought a pair of Sony headphones which i would like to make wireless change so I also bought a crappy wireless coil meant to convert a phone into wireless charging. i opened the headphones, located the ground and 5v pin coming from the USB connected the circuit and surprise the charging led doesn't light ... The charging board is separated from the main board so I checked the flat cable that connects them, found the 5v and gnd ,spliced into it, and the led light lit as if it was charging. the next morning the led was of signaling the headphones are full, unfortunately after powering them on the battery status indicated was still 20% as the evening before ... Have I done anything wrong ? What about that phase when they negotiate the power output with a magic resistor ? What should I try next? Thanks in advance ๐Ÿ‘๐Ÿป

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[โ€“] [email protected] 1 points 5 months ago (1 children)

Thanks i Will make sure to connect only One at a time ... ๐Ÿ‘๐Ÿป

[โ€“] [email protected] 2 points 5 months ago* (last edited 5 months ago) (1 children)

Cheap power supplies being back-powered from the output will die. By connect together I mean put in the same circuit. Not use at the same time.

You're possibly powering the other power supply through the feedback resistors, ESD diodes, etc. You really want a controller that can share between the two sources or just 2 diodes if you can take the voltage drop

[โ€“] [email protected] 1 points 5 months ago

Oh now its clear i dont have a special controller neither the space to fit It inside the headphones so i will go the diode rout, if i pay attention not to plug them both in at the same time could I use only one for the wireless circuit ? How do I know if I can take the voltage drop ?