Grumpydaddy

joined 1 year ago
[–] [email protected] 2 points 5 days ago (3 children)

Are you saying that the rules did not strictly forbid this system prior to Miami and the underlined text was added to the regulations to eliminate the loophole RBR was using to help win?

[–] [email protected] 2 points 2 weeks ago

I think you want the screwdriver to seat as far down as possible so I would recommend you dig out the glue

[–] [email protected] 6 points 2 weeks ago (2 children)

The US missed out on both the Robertson screw head and the metric system!

[–] [email protected] 2 points 2 weeks ago (2 children)

If it is filled with glue then I would try scraping it out with the tip of a utility or xacto knife

[–] [email protected] 14 points 2 weeks ago* (last edited 2 weeks ago) (4 children)
  1. Strong down force with the appropriate screwdriver (looks like it started out as a Phillips head) while turning the driver with a wrench. You need a square shaft in your screwdriver or clamp with vice grips.

  2. Same, strong down force, but use a square driver ( Robertson screw). This can also be accompanied with a wrench.

  3. Drill it out. This is pretty much the last resort as you will use a drill bit about the same size as the threads which will pretty much take the head of the screw off as you drill into the threads. The threads probably won't come out but you will at least be able to open the case. I have had very little luck with screw extractors and they probably don't come that small.

Strong down force is the main thing I have found to work when breaking loose pesky screws. Pushing down hard enough to prevent the bit from skipping to the next slot

 
 

Kind of an ELI5, but I tune a radion into a specific frequency to listen to a station. If that frequency is constantly being modulated (changed), how is the radio not going in and out of tune? I expect it is finding a way to measure multiple frequencies around the tuned station and decodes the data from it's deviation from the tuned frequency?

[–] [email protected] 3 points 1 month ago (1 children)

So for common folk like myself, what do I need to do? I used Authy for a few sites. Can a bad actor pretending to be me now get access to those sites?

[–] [email protected] 8 points 1 month ago (1 children)

They already have, no?

[–] [email protected] 1 points 2 months ago

There has always been a pretty large gap between Perez and Max in terms of performance. It's been speculated that it is more a matter of the competition's cars getting faster than Perez's performance declining. They have found a way to catch up with Red Bull car and only Max's skill is keeping them ahead.

[–] [email protected] 3 points 2 months ago (2 children)

Perez failed to make it past the first qualifying round, finishing 16th, while his teammate, Max, grabbed the number two spot for tomorrow's race.

[–] [email protected] 49 points 2 months ago (1 children)

Cool ceiling tile

[–] [email protected] 3 points 3 months ago

That's always been my argument, revoke citizenship and deport anyone caught hiring illegal aliens. But that's not what any of this is really about.

[–] [email protected] 6 points 3 months ago* (last edited 3 months ago) (3 children)

It did, a quick search turns up a dedicated bombing campaign using zepplins. Who would have thought!

 

I'm trying to understand what's happening in this circuit:

I------------------T1 (+333V)
I                 I
I                 R1(10K)
(pos)             I
1000V             I------------gnd (0V)
(neg)             I
I                 R2(10K)
I                 I
I                 IT2(-333V)
I                 I
I                 R3(10K)
I                 I
I-----------------IT3 (-666.7V)

I am learning basic DC theory from reading and sometimes I come across something I'd like to ask a question about, so:

  1. In the above circuit, without the ground, the voltage across all components would begin at 10V and finish at 0V. By adding a ground, I'm basically saying "here is 0V" and everything gets redefined in reference to that point and I end up with a 10 volt circuit with +3.33 as it's highest voltage and -6.667 as it's lowest.

  2. The electrons could care less, they still flow from the anode to the cathode of the battery under normal conditions, going from the highest potential to the lowest.

  3. This example was only used to demonstrate voltage dividers. It revolved around worker protection present in aluminum processing. Each machine is in series and mobile grounds are used nearest the machine a worker is using. I assume that this allows the worker to have the least exposure to electrical shock as they are also at ground potential?

I actually think working though these questions has cleared everything up, but please, comment on anything I got wrong.

Also, sorry about the crappy drawing, the autowrap in this editor really made things tough to format

Thanks!

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