this post was submitted on 11 Sep 2024
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Witchcraft (mander.xyz)
submitted 1 month ago* (last edited 1 month ago) by [email protected] to c/[email protected]
 
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[–] [email protected] 5 points 1 month ago* (last edited 1 month ago) (1 children)

1/(n * (n+1)) = 1/n - 1/(n+1)

1/(1 * 2) + 1/(2 * 3) + 1/(3 * 4) + ... = 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... = 1

[–] [email protected] 6 points 1 month ago* (last edited 1 month ago)

Written a bit more explicitly (although I kinda handwaved away the final term--the point is that you end up with one unpaired term which goes to zero)

edit: I was honestly confused about how exactly this related to the question, but seeing the comment from @[email protected] (not visible from Hexbear) which showed that the first sum in the image is equivalent to

the sum from n = 1 to ∞ of 2/(n * (n + 1))

made things clear (just take the above, put 2 in the numerator, and you get a result of 2)