this post was submitted on 03 Aug 2023
387 points (95.5% liked)

Programmer Humor

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[–] [email protected] 59 points 1 year ago (3 children)

Should have used python. The answer is youme.

[–] [email protected] 15 points 1 year ago (5 children)

Most languages support concatenation of strings using the + operator. The only mainstream languages I can think of that don't are PHP (which uses ".") and low-level languages like C & C++.

[–] [email protected] 12 points 1 year ago

JavaScript might even concatenate some integers instead of adding them just for shits and giggles.

[–] [email protected] 9 points 1 year ago

R uses paste0() for some reason

[–] [email protected] 6 points 1 year ago

Lua uses ..

[–] [email protected] 5 points 1 year ago (1 children)

C++ does as well, doesn't it? Though I don't often use std::string, so I'm not sure. But every other string type I worked with had + overloaded.

[–] [email protected] 2 points 1 year ago

I dunno, I've never actually worked in C++, but I tried it out online and it didn't seem to work.

[–] [email protected] 2 points 1 year ago (3 children)
[–] [email protected] 1 points 1 year ago

Using the C++ standard library beyond the C backwards compatible parts? What devilry is this‽

[–] [email protected] 1 points 1 year ago

I think your link has a double encoded % at the end: %25

The correct link is https://en.cppreference.com/w/cpp/string/basic_string/operator2B

[–] [email protected] 1 points 1 year ago* (last edited 1 year ago) (1 children)

I ran

#include 
#include 

int main()
{
  std::string name;
  std::cout << "you"+"me";
}

Using cpp.sh, and got the following error:

main.cpp:7:21: error: invalid operands to binary expression ('const char[4]' and 'const char[3]')
  std::cout << "you"+"me";
               ~~~~~^~~~~
1 error generated.
[–] [email protected] 1 points 1 year ago

This is because your operands are const char[]. That's not a std::string.

[–] [email protected] 8 points 1 year ago

Only if you put "you" and "me" in quotation marks.

[–] [email protected] 1 points 1 year ago

The answer is false. youme !<3

[–] [email protected] 25 points 1 year ago* (last edited 1 year ago) (1 children)

If you are one and I am one then you plus me is love.

you = 1

me = 1

you + me < 3

[–] [email protected] 10 points 1 year ago

You may try to divide us but we'll always be as one.

[–] [email protected] 22 points 1 year ago* (last edited 1 year ago) (3 children)

My brain is too mushy to do it myself right now, but I wonder what the result would be if we were to consider the alphabet a base-26 number system and added the numbers that correspond to those letters.

[–] [email protected] 11 points 1 year ago

I feel like javascript would actually do this :P

[–] [email protected] 4 points 1 year ago

Pepsi?

Extra credit!

[–] [email protected] 2 points 1 year ago

💞💞💞zby

[–] [email protected] 20 points 1 year ago (1 children)
[–] [email protected] 10 points 1 year ago (1 children)
[–] [email protected] 2 points 1 year ago

[object Object]

[–] [email protected] 12 points 1 year ago

Honestly dodged a bullet there when they can’t even get their errors straight. Obviously an undefined variable you and me would be more appropriate. Duh. 👯‍♀️

[–] [email protected] 10 points 1 year ago

When js is ur bf/gf:

84

49

36

59

youme

[–] [email protected] 4 points 1 year ago

Less than three

..unless 😳

[–] [email protected] 3 points 1 year ago

I know my calculus. It says you+me = us

Stupid AI!

[–] [email protected] 2 points 1 year ago

I am the mayor of Bonetown — Population: you and me.